两位数除法和个位数除法非常相似，其中会涉及一些个位数除法中没有的乘法运算。
步骤
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1
采用长除法的格式：
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2“猜”下结果的第一位数字应该是什么，然后写下这个数字：
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3
把这个数字和除数相“乘”(我们所举的例子中，除数是28) 把乘得结果写在原被除数下方。
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4把被除数和第三步中得到的乘积相“减”
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5
继续“猜-乘-减”的过程，直至减得的结果为零或小于零。
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6
决定下如何处理余数。当减得结果小于除数时，我们称该结果为余数。你可以把余数作为分子，除数作为分母。
- 在我们所举的例子中，答案将是8又12/ 28 ，可以化简为8又 3/ 7。
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7
如果你想获得小数，你需要在原来的被除数后添加一个“ .0”。（在我们的例子中，236就变为236.0 ）
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8把零沿着竖直方向放到你最后的余数结果后
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9
“猜”一下这个新的小计结果里面有多少个除数，并写下来。
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10
再“乘”。
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11...“减”
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12
继续重复“猜-乘减”的过程” ，直到小数位数足够精确或减得结果为零。
小提示
- 在这个例子中，我们的除数是28 。请记住， 10× 28 = 280 ，5 × 28 =140是280的一半。由于236在280和140之间，你的第一个猜测应该在5和10之间。
警告
- 如果你的减得结果是一个负数，那你猜的数就太大了。请尝试一个较小的猜测。
- 如果你的减法结果大于除数，那你猜的数不够大。请尝试一个更大的猜测。
你需要准备